Code · 2009-01-06

基于PHP的简单4人排班系统

前些日子因为工作需要,做了个在线的4个人轮班的排班表系统,功能很简单,就是按人数与天数来生成一份排班表。
分别需要填写”昨日的早班与夜班” “今日的早班与晚班” “日期的开始与结束”
点击这里看预览






Four Shift Roster

don't hesitate to let me know if you have any question.
author: 小桥流水人家
Yesterday
Day Shift Night Shift

Today
Day Shift Night Shift
Date
Autual Starting Date       The End Date

31 ) { echo 'Input ERROR,plz check again!'; exit(); } if ($end>31) { echo 'input ERROR,plz check again!'; exit(); } if (!is_int($start) || !is_int($end)) { echo 'do you have input a number?'; exit(); } function class_output() { global $name1; global $name2; global $name3; global $name4; global $start; global $end; $content=array( 'a'=>array( array('name'=>$name1,'class'=>'Day Shift','state'=>'open'), array('name'=>$name2,'class'=>'Night Shift','state'=>'open') ), 'b'=>array( array('name'=>$name3,'class'=>'Day Shift','state'=>'close'), array('name'=>$name4,'class'=>'Night Shift','state'=>'close') ) ); ?> $value) { if ($value[0]['state']=='open') { echo ''; if ($value[0]['class']=='Day Shift') { echo ''; echo ''; echo ''; } else { echo ''; echo ''; echo ''; } echo ''; } } } } class_output(); } ?>
Date Day Shift Night Shift
'.$date.''.$value[0]['name'].''.$value[1]['name'].''.$date.''.$value[1]['name'].''.$value[0]['name'].'